-16x^2+18x+100=0

Solution for -16x^2+18x+100=0 equation:

-16x^2+18x+100=0

a = -16; b = 18; c = +100;
Δ = b2-4ac
Δ = 182-4·(-16)·100
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6724}=82$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-82}{2*-16}=\frac{-100}{-32}
=3+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+82}{2*-16}=\frac{64}{-32}
=-2
$